# Problem B

Canonical Coin Systems

A *coin system* $S$ is a finite (nonempty) set of
distinct positive integers corresponding to coin values, also
called *denominations*, in a real or imagined monetary
system. For example, the coin system in common use in Canada is
$\{ 1,5,10,25,100,200\} $,
where $1$ corresponds to a
$1$-cent coin and $200$ corresponds to a $200$-cent ($2$-dollar) coin. For any coin
system $S$, we assume that
there is an unlimited supply of coins of each denomination, and
we also assume that $S$
contains $1$, since this
guarantees that any positive integer can be written as a sum of
(possibly repeated) values in $S$.

Cashiers all over the world face (and solve) the following
problem: For a given coin system and a positive integer amount
owed to a customer, what is the smallest number of coins
required to dispense exactly that amount? For example, suppose
a cashier in Canada owes a customer $83$ cents. One possible solution is
$25+25+10+10+10+1+1+1$,
i.e., $8$ coins, but this
is not optimal, since the cashier could instead dispense
$25+25+25+5+1+1+1$, i.e.,
$7$ coins (which
*is* optimal in this case). Fortunately, the Canadian
coin system has the nice property that the *greedy
algorithm* always yields an optimal solution, as do the
coin systems used in most countries. The greedy algorithm
involves repeatedly choosing a coin of the largest denomination
that is less than or equal to the amount still owed, until the
amount owed reaches zero. A coin system for which the greedy
algorithm is always optimal is called *canonical*.

Your challenge is this: Given a coin system $S = \{ c_1, c_2, \ldots , c_ n\} $,
determine whether $S$ is
canonical or non-canonical. Note that if $S$ is non-canonical then there exists
at least one *counterexample*, i.e., a positive integer
$x$ such that the minimum
number of coins required to dispense exactly $x$ is less than the number of coins
used by the greedy algorithm. An example of a non-canonical
coin system is $\{ 1,3,4\}
$, for which $6$ is
a counterexample, since the greedy algorithm yields
$4+1+1$ ($3$ coins), but an optimal solution is
$3+3$ ($2$ coins). A useful fact (due to
Dexter Kozen and Shmuel Zaks) is that if $S$ is non-canonical, then the
smallest counterexample is less than the sum of the two largest
denominations.

## Input

Input consists of a single case. The first line contains an integer $n$ $(2 \leq n \leq 100)$, the number of denominations in the coin system. The next line contains the $n$ denominations as space-separated integers $c_1 \ c_2 \ \ldots \ c_ n$, where $c_1 = 1$ and $c_1 < c_2 < \ldots < c_ n \leq 10^6$.

## Output

Output “`canonical`” if the coin
system is canonical, or “`non-canonical`” if the coin system is
non-canonical.

Sample Input 1 | Sample Output 1 |
---|---|

4 1 2 4 8 |
canonical |

Sample Input 2 | Sample Output 2 |
---|---|

3 1 5 8 |
non-canonical |

Sample Input 3 | Sample Output 3 |
---|---|

6 1 5 10 25 100 200 |
canonical |