# Judging Moose

The point system works like this: If the number of tines on the left side and the right side match, the moose is said to have the even sum of the number of points. So, “an even $6$-point moose”, would have three tines on each side. If the moose has a different number of tines on the left and right side, the moose is said to have twice the highest number of tines, but it is odd. So “an odd $10$-point moose” would have $5$ tines on one side, and $4$ or less tines on the other side.

Can you figure out how many points a moose has, given the number of tines on the left and right side?

## Input

The input contains a single line with two integers
$\ell $ and $r$, where $0 \le \ell \le 20$ is the number of
tines on the *left*, and $0 \le r \le 20$ is the number of
tines on the *right*.

## Output

Output a single line describing the moose. For even pointed
moose, output “`Even $x$`” where $x$ is the points of the moose. For
odd pointed moose, output “`Odd
$x$`” where
$x$ is the points of the
moose. If the moose has no tines, output “`Not a moose`”

Sample Input 1 | Sample Output 1 |
---|---|

2 3 |
Odd 6 |

Sample Input 2 | Sample Output 2 |
---|---|

3 3 |
Even 6 |

Sample Input 3 | Sample Output 3 |
---|---|

0 0 |
Not a moose |